Modern benzene bonding indicates that all C-C bonds are equal in length due to resonance; Which option expresses this modern understanding?

Modern benzene bonding indicates that all C-C bonds are equal in length due to resonance; Which option expresses this modern understanding?

• A. Benzene contains alternating single and double bonds
• B. All C-C bonds in benzene are equal in length due to resonance
• C. Benzene has three double bonds and three singles
• D. Benzene has only single bonds

Answer: (B)

Benzene’s modern bonding picture rests on resonance and delocalization of its pi electrons around the ring. The six pi electrons are shared by all six carbon atoms, not confined to three separate double bonds. This delocalization creates bonds that are intermediate in character between a single and a double bond, so every C–C bond ends up with the same length—about 1.39 Å. That uniform bond length is a hallmark of the resonance hybrid, reflecting aromatic stabilization. Representations that show alternating single and double bonds would predict two different bond lengths, which isn’t what’s observed. Saying there are three double bonds and three singles similarly implies bond localization and different lengths. And claiming only single bonds ignores the evidence of pi bonding and the observed bond lengths. The statement that all C–C bonds are equal in length due to resonance captures the actual delocalized nature of benzene.

Benzene’s modern bonding picture rests on resonance and delocalization of its pi electrons around the ring. The six pi electrons are shared by all six carbon atoms, not confined to three separate double bonds. This delocalization creates bonds that are intermediate in character between a single and a double bond, so every C–C bond ends up with the same length—about 1.39 Å. That uniform bond length is a hallmark of the resonance hybrid, reflecting aromatic stabilization.

Representations that show alternating single and double bonds would predict two different bond lengths, which isn’t what’s observed. Saying there are three double bonds and three singles similarly implies bond localization and different lengths. And claiming only single bonds ignores the evidence of pi bonding and the observed bond lengths. The statement that all C–C bonds are equal in length due to resonance captures the actual delocalized nature of benzene.